Integrand size = 8, antiderivative size = 67 \[ \int x^3 \text {arcsinh}(a x) \, dx=\frac {3 x \sqrt {1+a^2 x^2}}{32 a^3}-\frac {x^3 \sqrt {1+a^2 x^2}}{16 a}-\frac {3 \text {arcsinh}(a x)}{32 a^4}+\frac {1}{4} x^4 \text {arcsinh}(a x) \]
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Time = 0.02 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {5776, 327, 221} \[ \int x^3 \text {arcsinh}(a x) \, dx=-\frac {3 \text {arcsinh}(a x)}{32 a^4}-\frac {x^3 \sqrt {a^2 x^2+1}}{16 a}+\frac {3 x \sqrt {a^2 x^2+1}}{32 a^3}+\frac {1}{4} x^4 \text {arcsinh}(a x) \]
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Rule 221
Rule 327
Rule 5776
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} x^4 \text {arcsinh}(a x)-\frac {1}{4} a \int \frac {x^4}{\sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {x^3 \sqrt {1+a^2 x^2}}{16 a}+\frac {1}{4} x^4 \text {arcsinh}(a x)+\frac {3 \int \frac {x^2}{\sqrt {1+a^2 x^2}} \, dx}{16 a} \\ & = \frac {3 x \sqrt {1+a^2 x^2}}{32 a^3}-\frac {x^3 \sqrt {1+a^2 x^2}}{16 a}+\frac {1}{4} x^4 \text {arcsinh}(a x)-\frac {3 \int \frac {1}{\sqrt {1+a^2 x^2}} \, dx}{32 a^3} \\ & = \frac {3 x \sqrt {1+a^2 x^2}}{32 a^3}-\frac {x^3 \sqrt {1+a^2 x^2}}{16 a}-\frac {3 \text {arcsinh}(a x)}{32 a^4}+\frac {1}{4} x^4 \text {arcsinh}(a x) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.73 \[ \int x^3 \text {arcsinh}(a x) \, dx=\frac {a x \left (3-2 a^2 x^2\right ) \sqrt {1+a^2 x^2}+\left (-3+8 a^4 x^4\right ) \text {arcsinh}(a x)}{32 a^4} \]
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Time = 0.01 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.87
method | result | size |
derivativedivides | \(\frac {\frac {a^{4} x^{4} \operatorname {arcsinh}\left (a x \right )}{4}-\frac {a^{3} x^{3} \sqrt {a^{2} x^{2}+1}}{16}+\frac {3 a x \sqrt {a^{2} x^{2}+1}}{32}-\frac {3 \,\operatorname {arcsinh}\left (a x \right )}{32}}{a^{4}}\) | \(58\) |
default | \(\frac {\frac {a^{4} x^{4} \operatorname {arcsinh}\left (a x \right )}{4}-\frac {a^{3} x^{3} \sqrt {a^{2} x^{2}+1}}{16}+\frac {3 a x \sqrt {a^{2} x^{2}+1}}{32}-\frac {3 \,\operatorname {arcsinh}\left (a x \right )}{32}}{a^{4}}\) | \(58\) |
parts | \(\frac {x^{4} \operatorname {arcsinh}\left (a x \right )}{4}-\frac {a \left (\frac {x^{3} \sqrt {a^{2} x^{2}+1}}{4 a^{2}}-\frac {3 \left (\frac {x \sqrt {a^{2} x^{2}+1}}{2 a^{2}}-\frac {\ln \left (\frac {a^{2} x}{\sqrt {a^{2}}}+\sqrt {a^{2} x^{2}+1}\right )}{2 a^{2} \sqrt {a^{2}}}\right )}{4 a^{2}}\right )}{4}\) | \(90\) |
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Time = 0.25 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.88 \[ \int x^3 \text {arcsinh}(a x) \, dx=\frac {{\left (8 \, a^{4} x^{4} - 3\right )} \log \left (a x + \sqrt {a^{2} x^{2} + 1}\right ) - {\left (2 \, a^{3} x^{3} - 3 \, a x\right )} \sqrt {a^{2} x^{2} + 1}}{32 \, a^{4}} \]
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Time = 0.27 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.91 \[ \int x^3 \text {arcsinh}(a x) \, dx=\begin {cases} \frac {x^{4} \operatorname {asinh}{\left (a x \right )}}{4} - \frac {x^{3} \sqrt {a^{2} x^{2} + 1}}{16 a} + \frac {3 x \sqrt {a^{2} x^{2} + 1}}{32 a^{3}} - \frac {3 \operatorname {asinh}{\left (a x \right )}}{32 a^{4}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]
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Time = 0.18 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.88 \[ \int x^3 \text {arcsinh}(a x) \, dx=\frac {1}{4} \, x^{4} \operatorname {arsinh}\left (a x\right ) - \frac {1}{32} \, {\left (\frac {2 \, \sqrt {a^{2} x^{2} + 1} x^{3}}{a^{2}} - \frac {3 \, \sqrt {a^{2} x^{2} + 1} x}{a^{4}} + \frac {3 \, \operatorname {arsinh}\left (a x\right )}{a^{5}}\right )} a \]
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Exception generated. \[ \int x^3 \text {arcsinh}(a x) \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int x^3 \text {arcsinh}(a x) \, dx=\int x^3\,\mathrm {asinh}\left (a\,x\right ) \,d x \]
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